#include<iostream>
  #include<cstdio>
  #include<cstring>
  using namespace std;
  int m,s,t;// 法力，距离，时间
 struct node
 {
      int juli;// 距离 
      int fali;// 法力 
     int shanshuo;
 }dp[300001];
 int main()
 {
     scanf("%d%d%d",&m,&s,&t);
     dp[0].fali=m;
     for(int i=1;i<=t;i++)
     {
         if(dp[i-1].fali>=10)
         {
             dp[i].fali=dp[i-1].fali-10;
             dp[i].shanshuo=dp[i-1].shanshuo+60;
         }
         else
         {
             dp[i].fali=dp[i-1].fali+4;
             dp[i].shanshuo=dp[i-1].shanshuo;
         }
         dp[i].juli=max(dp[i-1].juli+17,dp[i].shanshuo);
     }
     if(dp[t].juli>s)
     {
         for(int i=0;i<=t;i++)
         {
             if(dp[i].juli>s)
             {
                printf("Yes\n%d",i);
                 return 0;
             }
         }
    }
     else
     {
         printf("No\n%d",dp[t].juli);
         return 0;
   }
    return 0;
 }

来一发滚动数组优化dp

#include <bits/stdc++.h>
using namespace std;
int n, m, t, sum1, sum2;
int main() {
	freopen("escape.in", "r", stdin);
	freopen("escape.out", "w", stdout); 
	cin >> m >> n >> t;
	for (int i = 1; i <= t; i ++) {
		sum1 += 17;
		if (m >= 10) m -= 10, sum2 += 60;
		else m += 4;
		sum1 = max(sum1, sum2);
		if (sum1 > n) {
			printf("Yes\n%d\n", i);
			return 0;
		}
	}
	printf("No\n%d\n", sum1);
	return 0;
}

6

#include<bits/stdc++.h> using namespace std; int main() { int m,s,t,now=0; cin>>m>>s>>t; int s1=0,s2=0; for(int i=1;i<=t;i++) { s1+=17; if(m>=10) { s2+=60; m-=10; } else m+=4; if(s2>s1) s1=s2; if(s1>s) { cout<<"Yes"<<endl<<i<<endl; return 0; } } cout<<"No"<<endl<<s1<<endl; return 0; }