6 条题解

  • 0
    @ 2025-11-13 15:16:54

    #include <iostream> using namespace std;

    int main() { int m, n; cin >> m >> n; int seats[100][100]; for (int i = 0; i < m; i++) { for (int j = 0; j < n; j++) { cin >> seats[i][j]; } }

    int k; cin >> k; int count = 1; for (int i = 0; i < m; i++) { for (int j = 0; j < n; j++) { if (seats[i][j] == 0) { if (count == k) { cout << i + 1 << " " << j + 1 << endl; return 0; } count++; } } } return 0;

    }

    信息

    ID
    101
    时间
    1000ms
    内存
    256MiB
    难度
    8
    标签
    递交数
    89
    已通过
    15
    上传者